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Webb24 maj 2013 · =2a 2-2a 2-5a+10=0 -5a+10=0 -5a=-10 a=-10/-5 So, a=2 . 23 ; X+a is a factor of 2x²+2ax+5x+10 therefore f(-a)=0; substituting values, 2(-a)²+2(a)(-a)+5(-a)+10=0 2a²-2a²-5a+10=0 -5a+10=0 therefore a=2. 4 ; By the division method, 8 ; Solution of the question. 0 ; About Us; Blog; Terms ... WebbAlgebra. Factor 2a^2-5a-12. 2a2 − 5a − 12 2 a 2 - 5 a - 12. For a polynomial of the form ax2 +bx+ c a x 2 + b x + c, rewrite the middle term as a sum of two terms whose product is … openglshext
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